Bernouille's Equation (Water through glass tube)?

I've literally been going at this question for hours and it's the last one I need to finish.

Here's a link to the diagram and question: http://img600.imageshack.us/img600/6932/tubequesti...

Anyways, here's what I tried:

P1 + 1/2(Rho)(v1)^2 + (Rho)(g)(y) = P2 + 1/2(Rho)(v2)^2 + (Rho)(g)(y) -> no change in y so term 3 is 0.

Put v1 in terms of v2

A1 = 1/10(A2)

therefore v1 = 10(v2)

P1 + 1/2(Rho)(10 x v2)^2 = P2 + 1/2(Rho)(v2)^2

P1 + 1/2(1000)(3)^2 = 200000 + 1/2(1000)(.3)^2

P1 = 200000 - 4455

P1 = 195545 Pa

Answer key says: 1.55x10^4 Pa