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Einsteininium
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Einsteininium asked in Science & MathematicsMathematics · 1 decade ago

Having trouble with area under the curve problem?

area above the x-axis between these x values: x=square root 3 over 2 and x=1/2 for the graph of

y=1/ square root of 1-x^2

supposedly the solution is as simple as sin inverse 1/2 minus sin inverse radical3 over 2. I must be missing something though.

2 Answers

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  • B B
    1 decade ago
    Favorite Answer

    Yes. You're missing that sqrt(3) /2 is greater than 1/2. So, you have to solve arc sin[sqrt(3) /2] - arc sin(1/2). Answer is pi/6

  • Shiva
    1 decade ago

    Dude, rephrase the question...browsers think that you are "having trouble with area under the curve"

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