Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and beginning April 20th, 2021 (Eastern Time) the Yahoo Answers website will be in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.
Trending News
Algebra 2 problem help?
tom spent a third of his life to date in the United States, a sixth in India, twelve years in Egypt, half the remainder of his time in Australia, and as long in Canada as he spent in India. where did he spend his fortieth birthday?
Use an algebraic equation to solve the problem. Explain your answer
1 Answer
- Anonymous1 decade agoFavorite Answer
Hi,
Let's let L = Tom's Age in years.
Then we need to translate each statement into algebraic equations
Then we're going to solve for L so we can figure out how many years he spent in each location
1/3 of his life in U.S., so U.S. = 1/3 L
1/6 in India, so India = 1/6 L
Egypt = 12
Australia = half of the remainder, which is half of [ L (the total) - the time spent in the first 3 countries]
1/2 (L - 1/3L - 1/6L - 12)
= 1/2 (6/6 L - 2/6 L -1/6L -12)
= 1/2 (1/2 L - 12)
= 1/4 L -6
Canada = 1/6 L (same as india)
The total must add to L (assuming these are everywhere he's lived)
1/3 L + 1/6 L + 12 +1/4L -6 +1/6 L = L the combine like therms
2/3 L +1/4 L + 6 = 1 L
1/4L + 6 = 1/3 L
3/12 L + 6 = 4/ 12 L
1/12 L = 6
L = 72 <-------he's 72 years old
Then plug back in:
He spent 24 years in the U.S.
12 in India (this is from 24-36 years old)
12 in Egypt (this is from 36-48 years old)
12 in Australia
12 in Canada
So he was in Egypt during year 40.
Good luck!
-Devon Review