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VA asked in Education & ReferenceHomework Help · 1 decade ago

Algebra 2 problem help?

tom spent a third of his life to date in the United States, a sixth in India, twelve years in Egypt, half the remainder of his time in Australia, and as long in Canada as he spent in India. where did he spend his fortieth birthday?

Use an algebraic equation to solve the problem. Explain your answer

1 Answer

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  • Anonymous
    1 decade ago
    Favorite Answer

    Hi,

    Let's let L = Tom's Age in years.

    Then we need to translate each statement into algebraic equations

    Then we're going to solve for L so we can figure out how many years he spent in each location

    1/3 of his life in U.S., so U.S. = 1/3 L

    1/6 in India, so India = 1/6 L

    Egypt = 12

    Australia = half of the remainder, which is half of [ L (the total) - the time spent in the first 3 countries]

    1/2 (L - 1/3L - 1/6L - 12)

    = 1/2 (6/6 L - 2/6 L -1/6L -12)

    = 1/2 (1/2 L - 12)

    = 1/4 L -6

    Canada = 1/6 L (same as india)

    The total must add to L (assuming these are everywhere he's lived)

    1/3 L + 1/6 L + 12 +1/4L -6 +1/6 L = L the combine like therms

    2/3 L +1/4 L + 6 = 1 L

    1/4L + 6 = 1/3 L

    3/12 L + 6 = 4/ 12 L

    1/12 L = 6

    L = 72 <-------he's 72 years old

    Then plug back in:

    He spent 24 years in the U.S.

    12 in India (this is from 24-36 years old)

    12 in Egypt (this is from 36-48 years old)

    12 in Australia

    12 in Canada

    So he was in Egypt during year 40.

    Good luck!

    -Devon Review

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