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Kinetic energy of rolling hoop...?
A 2.80 kg hoop 2.20 m in diameter is rolling to the right without slipping on a horizontal floor at a steady 3.00 rad/s.
I calculated that its linear speed is 3.3 m/s. What's its kinetic energy?
Apparently that's not the answer they're looking for, kamran. The question is "What is the total kinetic energy of the hoop?"
I got help from the textbook. The formula was .5(m)v^2 + .5(I)w^2 = 30.5 J. Thanks for the effort though.
1 Answer
- 1 decade agoFavorite Answer
KE = (0.5) * (2.80 kg) * (3.3 m/s)2 = 15.246
Kinetic energy is the energy of motion. An object that has motion - whether it is vertical or horizontal motion - has kinetic energy. There are many forms of kinetic energy - vibrational (the energy due to vibrational motion), rotational (the energy due to rotational motion), and translational (the energy due to motion from one location to another). To keep matters simple, we will focus upon translational kinetic energy. The amount of translational kinetic energy (from here on, the phrase kinetic energy will refer to translational kinetic energy) that an object has depends upon two variables: the mass (m) of the object and the speed (v) of the object.
