solve the equation4(x-3) +7=23?

Hi,

4(x-3)+7 = 23

4(x-3) = 16

x - 3 = 4

x = 7

Cheers,

Bogdan

X=16

Here is how to solve it:

4(x-3)+7=23

Use distributive property (Multiply x by 4 and -3 by 4)

4x-12+7=23

Combine like terms (-12+7)

4x-5=23

Inverse operations (Add 5 to -5 and 23)

4x=28

Divide both sides by 4 (4/4 and 28/4)

x=7

x=7. 7-3=4. 4(4)plus 7=23

Use the distributive property

4x + -12 + 7 = 23

4x + -5 + 23

add 5 to both sides

4x = 28

x = 7

First step: Multiply everything inside the parenthesis by the 4 outside the parenthesis. 4 times x and four times negative three. This would give you 4x -12.

Second step: Plug that information into the rest of the equation. 4x - 12 +7 = 23

Third step: Combine like terms on the left side of the equation. 4x (-12 + 7) = 23 becomes 4x - 5 = 23

Fourth step: Isolate x on one side of the equation by adding 5 to BOTH sides of the equation. 4x - 5 + 5 = 23 + 5 becomes 4x = 28

Fifth step: Solve for x by dividing both sides of the equation by 4 (4x/4) = (28/4) becomes x = ? ( I can't do the WHOLE thing for ya... hehe)

Hope this helps. The main thing to remember is that you need to get your variable isolated on one side, with all non-variables on the other. Follow your normal steps (PEMDAS... Parenthesis, exponents, multiplication, division, addition, subtraction) in order, and you should be fine.

Good luck!

x= 7.

Well firstly expand the brackets on the left hand side by multiplying 4 by (x-3) like so:

4x - 12 + 7 = 23

This obviously simplifies to 4x - 5 = 23

Now simply add 5 to both sides:

4x = 28

Now simply divide both sides by 4 to find x:

x = 7

There you go! Happy new year!

see dear

4(x-3)+7=23

=> 4x-12+7=23 [as 4Xx=4x and 4X3=12]

=>4x-5=23

=>4x=23+5=28

=>x=28/4

Thus, x=7

Hope i helped u

4(x-3) +7=23

4x - 12 + 7 = 23

4x = + 12 - 7 + 23

4x = 28

x = 7