put this in to slope y intercept form?

y= -2x+7

The y intercept form is y=mx + c, where m is the slope and c a constant.

4x + 2y = 14

2y = 14-4x

y = 7-2x

y= -2x + 7

4x+2y = 14

2y = 14 - 4x

y = - 2x + 7

divide both side by 14 you get y intercept as 7 and slope will be minus 2

y=mx+c is the y-intercept form.This is so because if x=0, y=m*0+c

therefore y=c, i.e., the line cuts the y-axis at y=c because for y-axis x=0.

4x+2y=14

=>2y= -4x+14

=>y= -2x+7

Here you go.

y=-2x+7 is the answer.

answer teh follo. question

Reduce the following inequality:(answer will be in d1,v1,a1 on one side and d2,v2,a2 on the other side. t1 and t2 will not be present in the answer )

t1^2v^2+a2^2t2^4+2t1va2t2^2 <=(v-v2)^2 t2^2-2a2 d2t2^2

where

t1=(- (v1 - v) - √v^2 + v1^2 -2 vv1 - 2a1 d1 )/a1

Important point is that v^2 + v1^2 -2 vv1 - 2a1 d1 is in the square root in the above equation

and

t2 =(- (2a2t1 +v2 -v) -√ (2a2t1 +v2 -v)^2 - a2 ( 2d2 +4v2t1 +4a2t1^2 ))/ a2

Important point is that (2a2t1 +v2 -v)^2 - a2 ( 2d2 +4v2t1 +4a2t1^2 is in the square root in the above equation

find

d1, v1, a1 (inequality relation to) d2, v2, a2

The following equations can be used to reduce the above inequality

a1t1^2 + (2v1 - 2v) t1+2d1 =0

a2t2^2 + t2(4a2t1 +2v2 -2v)+( 2d2 +4v2t1 +4a2t1^2 )=0

here a1 and a2 are the acc. of two objects(always positive)

v1 and v2 are the velocities of two objects

t1 and t2 are the time

v is the velocity of man.

Please reduce the inequality as early as possible and if find the solution then please mail me at pawan_intelligent88@yahoo.co.in

slope - int form is y = mx + b

2y = -4x + 14

y = -2x + 7

there ya go