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Question about heat/energy?
"A 100.0 gram sample of water at 27.0 degrees C is poured into a 70.1 gram sample of water at 89.0 degrees C. What will be the final temperature of the water?"
Please explain how you got the answer too.
1 Answer
- 1 decade agoFavorite Answer
since both of the samples are water,
we find the energies: Q=m*c*T
100*27*1cal/g*C = 2700 cal
70.1*89*1cal/g*C= 6239 cal
add them, 8939 cal and then divide by the total mass, 8939 cal/ 170.1 g = 52.55 cal/g
in order to find the temperature we have to divide by the specific heat capacity 1 cal/g*C
we get 52.55 degrees C.
