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The amount of pollutants a factory dumps into a river is approximately normally distributed with a mean of?
1. The amount of pollutants a factory dumps into a river is approximately normally distributed with a mean of 2.43 and a standard deviation of 0.88 tons. What is the probability that it dumps more than 3 tons?A) 0.2586
B) 0.2843
C) 0.6500
D) 0.7157
E) 0.7414
My answer is A.
4. The game of chuck-a-luck consists of rolling 3 dice. The player picks a number, 1, 2, 3, 4, 5, or 6. Winning and losing depends on the number of times the number appears on the top of each die. If the number appears once then the winnings are equal to the bet. If the number appears twice the winnings are twice the bet. If the number appears 3 times the winnings are 5 times the bet. If the number doesn't appear then the bet is lost. If the number 2 is chosen, what is the probabilty of winning at chuck-a-luck?
A) .167
B) .333
C) .417
D) .421
E) .500
My answer is C.
5. The game of chuck-a-luck consists of rolling 3 dice. The player picks a number, 1, 2, 3, 4, 5, or 6. Winning and losing depends on the number of times the number appears on the top of each die. If the number appears once then the winnings are equal to the bet. If the number appears twice the winnings are twice the bet. If the number appears 3 times the winnings are 5 times the bet. If the number doesn't appear then the bet is lost. A $5.00 bet is made on the number 3. what is the expected outcome of the bet?
A) 0.840
B) 1.354
C) 0.354
D) -0.354
My answer is B.
2 Answers
- Anonymous1 decade agoFavorite Answer
1/A
- DavidLv 71 decade ago
(3-2.43)/.88=.6477
P(z=.6477)=0.741419319
1 - .7414 = .2586
P(x>3)=.2586
it depends on what your definition of winning is.
you have a 1 - (5/6)^3 probability of rolling at least one 2
.421
you have a
3(1/6)(5/6)^2 probability of winning 5
3(1/6)^2(5/6) probability of winning 10
(1/6)^3 probability of winning 25
(5/6)^3 probabily of losing 5
15(1/6)(5/6)^2 + 30(1/6)^2(5/6) + 25(1/6)^3 - 5(5/6)^3 = -.3472