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Higher degree polynomial equations?
a) Find a cubic equation with roots 6, -1 and 3
b) Find a fourth degree equation with roots 1, 2, 3 and 5
3 Answers
- rdwnLv 41 decade agoFavorite Answer
a) sum of roots = 8
product and sum of roots = -6 + 18 - 3 = 9
product of roots = - 18
so cubic equation : x^3 - 8x^2 + 9x - 18 = 0
b) I have not done fourth degree polonomials in class, but i can guess....
(x - a)(x - b)(x - c)(x - d) = (x - d)[ x^3 - (a + b + c)x^2 +(ab + ac + bc)x - abc]
=x^4 -(a + b + c + d)x^3 + (ab + ac + bc + d(a +b + c))x^2 - (abc + d(ab + ac + bc))x + abcd
a = 1, b = 2 , c = 3 , d = 5 just substitute.
- N.D. PrabhakarLv 51 decade ago
a) (x-6)(x+1)(x-3) multiply first two, simplify, and then multiply by third term and simplify
b) (x-1)(x-2)(x-3)(x-5) proceed as above, first two, then third, then fourth, for example. Order does not matter, but best to be systematic to avoid errors.