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Intriguing Maths question?
Right so, i haven't done mathematics in a couple of years and was wondering if i'd answered this question correctly
"The Manager has agreed to make improvements to the coffee shop. During the work barriers will have to be put around the area. The barriers are made of posts and tapes that will reach up to 2m each.
Work-Barrier information
Each post has a tape which can be attached to the next post.
A single post and it's tape will reach up to 2m
The barrier will go around a rectangular space 5.5m by 7.5m
How many sets of posts and tapes will the workmen need to go round the space?
Right, so first i worked out the area of the rectangular space, 5.5m by 7.5m = 41.25m
I rounded the 41.25m up to 42m, because obviously you'd need to have posts and tape which cover more than the actual distance as opposed to less.
I then divided the 42 by 2, giving me 21 posts, now maybe that seems a bit much but i haven't done Maths in ages, so my minds a little sketchy when it comes to working things out
Any help would be much appreciated, thank you
2 Answers
- A HLv 61 decade ago
The key is that you're dealing with a PERIMETER, not an area. When you go AROUND something, it's a perimeter. When you include all the space inside, it's an area.
CORNER POSTS:
First you need 4 posts at the corners.
LENGTH POSTS:
For each of the two 5.5m lengths, you have to place one post at the 2m mark, and one post at the 4m mark. Once you place a post at the 4m mark, you can connect that post to the 5.5m mark, since 1.5m is less than 2m. Thus, you add two more posts to each of the two sides, giving a total of 4 posts along the length.
WIDTH POSTS:
For each of the two 7.5m widths, you have to place a post at the 2m, 4m, and 6m mark. That's a total of 6 posts. Again, you can hook the 6m post up to the 7.5m post, and you're golden.
Total number of posts: 4 + 4 + 6 = 14
- ?Lv 51 decade ago
Why would you need the area ? You just have to put the tape around the perimeter. For the shorter sides you would need 3 tapes (rounding 5.5 up to 6), for the longer sides you would need 4. In total, you would require 2*3 + 2*4 = 14 posts and tapes.
