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kvcreom
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Please I need help with a math equation....x^3-3x^2+4=0 It is very important?
Update:
please not just the result but all the steps too, thank you
Update 2:
ANOTHER ANSWER PLEASE
1 Answer
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- 1 decade agoFavorite Answer
possible rational roots= ±1, ±2, ±4
(x^3-3x^2+4)/(x+1)=x^2-4x+4
(x+1)(x^2-5x+4)=0
(x+1)(x-2)^2=0
x=-1 or (x-2)^2=0
x+2=0
Answer: x={-1, 2 multiplicity 2}; the other answer was just missing the multiplicity 2
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