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I'm having trouble with this math problem, can someone please help!?
I figured out the answer to (a) which is 2.81e9 and the answer for (b) is 5.11e11. Can someone please help me get part (c) because I am stuck on that question!
A freight version of Boeing's 747 airliner has 2.7×104 cubic feet of cargo space. A CD in its jewel case has a volume of 10.8 cubic inches. Assume that each CD holds 650 megabytes of information.
(a) If you packed the aircraft with as many CDs as it could hold, how much information could you store in megabytes?
(b) A "56K" modem typically transmits information at 45 kilobits per second. In computer terminology, a kilobit is 1024 bits, and a megabyte is 1,048,576 bytes. One byte equals eight bits of information. How long would it take to transmit the amount of information contained in one 747 planeful of CDs through a modem?
(c) A T3 high-speed internet connection transmits information at 45.0 megabits per second. As with bytes and bits, one megabyte equals eight megabits of information. Assume that it takes 12 hours to load, fly and unload the 747. How many T3 connections would it take to transmit this information in 12 hours?
1 Answer
- N.D. PrabhakarLv 51 decade agoFavorite Answer
Assuming your answer 2.81*(10^9) for (a), the answer to part (c) would be obtained as follows.
The amount of bits in a plane load of CDs is A=2.81*(10^9)*8
The amount of bits in one T3 connection that can be sent in one sec is 45*1048576/8
So the amount of bits in a T3 connection that can be sent in 1 hours is
B=(45*1048576/8)*3600
So the number of hours of T3 connections that would be needed to send one plane load of info. is
N=A/B
Using log to base 10,
log(N)=log(2.81)+9+log(8)-log(45)-log(1048576)+log(8)-log(3600)=(0.02477) so that
N=10^(0.02477)=1.0587 hours
Thus it will take 1.0587/12=0.0882 T3 connections operating for 12 hours to carry the info. in one plane load of CDs, or equivalently, one can carry about 11.33 planeloads of information in 12 hours on a single T3 connection.
Do check the calculations.
