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Anonymous
Anonymous asked in Science & MathematicsMathematics · 1 decade ago

I'm having trouble with this math problem, can someone please help!?

A truck moving at constant velocity 15 m/s passes a stationary car. At that instant the car begins to move with constant acceleration of 5 m/s^2. How far has the car moved when it overtakes the truck?

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  • 1 decade ago
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    A graph of truck and car velocity vs. time can be helpful to understanding. The area under each curve (line) will be the distance traveled.

    The car will overtake the truck when its average velocity matches that of the truck. Over a given interval, its average velocity will be the velocity it had halfway through the interval.

    The car's velocity matches that of the truck after (15 m/s)/(5 m/s^2) = 3 s. It will take 2*(3 s) = 6 s to overtake the truck. Both car and truck will have moved (6 s)*(15 m/s) = 90 m.

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