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Jet plane takeoff question?
A 2.75x10^6 N catapult jet plane is ready for takeoff. if the jet's engines supply a constant thrust at 6.35x10^6 N, how much runway will it need to reach it's minimum takeoff speed of 285 m/s?
Can I get some ideas on what formulas to use? How I should go about doing this question?
3 Answers
- Anonymous1 decade agoFavorite Answer
The mass of the plane is given i Newtons, so you need to divide by g to get the mass. Assume the plane starts from rest. Use Fres=ma to find the acceleration and then use V2^2=V1^2+2as
you know everything except s...
- ☼¿☼Lv 51 decade ago
divide 2.75x10^6 N by 9.8N/kg (the acceleration of gravity near the earth's surface)
according to Newton's Second Law, a=F/m. So divide the thrust force by its mass to obtain the rate of acceleration.
(V2)^2 = (V1)^2+2a*d
we know the final speed (V2) and the initial speed (V1) is 0m/s. we just found the acceleration to me F/m, and found the mass.
rearrange to solve for d:
d=(V2)^2/2a
now substitue and solve.
- Andrew SmithLv 71 decade ago
We want "s" the length of the runway.
We know "v" the final speed.
We can calculate "a" the acceleration. (F=ma so a =F/m)
So I would pick v^2= u^2 + 2 * a * s
Note that the initial velocity " u" is zero.