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grade 10 math question?
briefly:
there are nickels dimes and quarters, a total of 49 coins. total value $5.20. if there are 5 more dimes than all the nickel and quarters combined then how many of each type of coin are there?
1 Answer
- Ron WLv 71 decade agoFavorite Answer
Define variables.
Let n be the number of nickels
Let d be the number of dimes
Let q be the number of quarters
n + d + q = 49
5n + 10d + 25q = 520
d = n + q + 5
Divide both sides of the second equation by 5, and subtract (n+q) from both sides of the third equation. This gives you the system
n + d + q = 49
n + 2d + 5q = 104
-n + d - q = 5
Add the first and third equations:
2d = 54
d = 27
Put this in the first and second equations, and simplify:
n + 27 + q = 49
n + q = 22
n + 2*27 + 5q = 104
n + 5q = 50
Subtract:
4q = 28
q = 7
n = 22 - q = 22 - 7 = 15
