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Need some help with a math question, 10 points to the best/right answer. either or?
Solve for M: integral (from 1 to M) 1/x^2 = 2.
2 Answers
- 1 decade agoFavorite Answer
First we have to find the integral from 1 to M of 1/x^2.
Rewrite 1/x^2 as x^-2. When we integrate x^-2, we get 1/3x^3.
Then evaluate that from 1 to M:
By plugging in M for x we get 1/3M^3 , and by plugging in 1 for x we get 1/3(1)^3 = 1/3
To evaluate them we subtract the lower bound from the upper bound.
1/3M^3 - 1/3
Now set it equal to 2:
1/3M^3 - 1/3 = 2
And solve algebraically:
+1/3...
1/3M^3 = 7/3
*3M^3...
1 = 7M^3
/7...
1/7 = M^3
and take the third root...
1/thirdroot(7) = M
Hope this helps!
Source(s): Engineering student (I do a lot of math haha) - Anonymous1 decade ago
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