Physics decibel sound problem?

dB = 10 log ratio

dB = 10 log 6 = 7.78 dB

Actually that is the ratio, not the difference. Difference means subtraction, and that doesn't make sense here.

But if you really want the difference, it depends on the actual power levels involved, which you don't provide. And that would not be in dB.

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BillRussell you are still right, that is the difference, one is 8 dB louder than the other, so the difference between them is 8 dB and always will be so long as one "puts out 6 times the acoustic power" regardless of the actual sound power level of the stereos

i anticipate the sound intensity point is ninety dB SPL or Sound rigidity point. A dB is unitless, yet 0 dB SPL is comparable to an intensity of 10^-12 W/m^2. So ninety dB is a ingredient of 10^9 larger in intensity than 0 dB. The sound intensity in question is then 10^-3 W/m^2. purely multiply the above sound intensity cases the area of the ear drum and then multiply by way of the style of seconds in 9 hours.