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Help on verifying the identity in TRIG?
Here's the problem:
sin t csc((pi/2))-t) = tan t
I used one of the cofunction identities but I got stuck..can you help explain how to do this?
Thank you for explaining it. :)
I need to practice doing these problems so I can get better.
1 Answer
- Anonymous1 decade agoFavorite Answer
to make thing easier, ill write pi/2 as 90 since its 90 degrees
sin(A-B) = sinAcosB - cosAsinB
sin90 = 1
cos90 = 0
sin(90-t)
= sin90cos(t) - cos90sin(t)
= 1 x cos(t) - 0 x sin(t)
= cos(t)
(sin t)(csc(90-t))
= (sin t)(1/sin(90-t)) (since csc = 1 / sin)
= (sin t)/(sin(90-t))
= (sin t)/(cos t) (proven earlier)
= tan t