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basic physics????......?
the instant before a batter hits a 0.14 kilogram baseball \, the velocity of the ball is 45 m/s west. The instant after the batter hits the ball, the balls velocity is 35 m/s east. The bat and ball are in contact for 1.0x10^-2 sec.
what is the magnitude of average force that the bat exerts on the ball while they are in contact?
determine the magnitude and direction of the avg acceleration of the baseball while it is in contact with the bat?
1 Answer
- ?Lv 41 decade agoFavorite Answer
To calculate force, recall that F = m*a. Since we are not directly given an acceleration, we must calculate it through our given information. For orientation's sake, we'll say that east is the positive x direction and west is negative. Recall the formula for velocity, v = a*t. Given this, we will calculate a and use this to calculate F.
v = a*t -> a = v/t, v = v2 - v1 = 45m/s - (-35m/s) = 80m/s, t = 10^-2
a = (80m/s)/(10^-2s) = (10^2/1s)(80m/s) = 8000m/s^2
F = (0.14kg)(8000m/s^2) = 1120N
Doing this, we also calculated the magnitude and direction of a, which is 8000m/s^2 due east while it is in contact with the bat.
Hope this helps!
