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In a group of 15 people, 6 are left-handed and the rest are right-handed. What is the probability if...?
In a group of 15 people, 6 are left-handed and the rest are right-handed. If 7 people are selected at random from this group, find the probability that
a) 3 are left-handed and 4 are right-handed
b) all are right-handed
c) Jim and John, two of the left-handers, are selected
1 Answer
- RiskyLv 41 decade agoFavorite Answer
a) (6 choose 3)*(9 choose 4)/ (15 choose 7)
you want any combination of the 3 of the 6 left handed to be chose and and combination of the 4 of the 9 right handed and you need to divide out of the possible combinations
b) (6 choose 0)*(9 choose 7)/(15 choose 7)
same logic as above
c) (2 choose 2)*(13 choose 5)/(15 choose 7)
hypergeomtric but the categories are jim and john or everybody else
