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What is the chance that their offspring will be brown-eyed or blue-eyed?

A brown-eyed woman (B) whose father is blue-eyed is married to

a blue-eyed man (b). What is the chance that their offspring will be brown-eyed or blue-eyed?

Do we need the punnett square for this? If so, please illustrate it!

^_^

2 Answers

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  • 1 decade ago
    Favorite Answer

    You know that the woman is heterozygous and that the man is homozygous. Their child will get a (b) allele from her father in any case, and either a (b) or a (B) from her mother with equal probabilities.

    So 50% for any of their children to be brown-eyed, 50% to be blue-eyed.

    And all of their brown-eyed children will be heterozygous.

  • Anonymous
    1 decade ago

    of course the punnet square is required and it depends on several factors.1) whether the mother and father are hybrid or pure 2) between blue eyed and brown eyed which one is dominant and recessive

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