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4 statistics questions, my answers and my reasoning behind those answers are included?
NOT cheating, I am giving my honest answers and why I think those answers are correct. Please just tell me if I got it right or not.
1. You have a SRS of 200 college seniors selected from over 85000 college seniors across the country. 37% of the students indicate that they will attend graduate school the following year. The mean and standard deviation of this statistic are:A) 37, .000784
B) 74, .034
C) 74, .000784
D) .37, .034
E) Can't calculate the mean and standard deviation because the sample size is too small in comparison to the population.
2. A certain manufacturer claims that 15% of the candies they place in each bag are green in color. A 6 ounce bag of candies contains 200 pieces. What is the probability that a bag of candies selected at random would contain less than 25 green candies?
A) .161
B) .178
C) .0805
D) .632
E) None of these
3. The sampling distribution for samples of size 5 with p around .3 would be approximately normal.
A) True
B) False
4. Angus is an expert dart tosser. He hits the bullseye 85% of the time. If Angus tosses 400 darts what is his corresponding z-score for 50 or fewer misses of the bullseye?
A) 1.40
B) -1.40
C) 4.61
D) -4.61
1. D- Found the mean and standard deviation through the formulas.
2. E- Got the z score as -1, which on the z score chart comes out to .8413 so 1-.8413 = a value that isn't an option.
3. B-False.
4. A- (Well, B is technically a right answer too because the z score is for both negative and positive) C and D had too high of a probability.
2 Answers
- Anonymous1 decade agoFavorite Answer
1. D correct.
2. z = (25.5 - 30)/5.05 = -0.891 ----> P(z < -0.891) = 0.187 E
(25.5 uses continuity correction.)
3. False correct.
4. 50 or fewer misses is 350 or more hits.
z = (350 - 340)/7.14 = 1.4
(z = -1.4 would be wrong. This would correspong to 330 or fewer hits.)
- Anonymous4 years ago
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