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Question based on Quadratic Equations?
If A and B are the roots of the equation x^2 + 4x + 5 = 0
Then the equation whose roots are (A + 1) and (B + 1) is
a ) x^2 + 2x + 2 = 0
b ) x^2 - 2x + 2 = 0
c ) x^2 - 2x - 2 = 0
d ) x^2 + 2x - 2 = 0
Also tell how U got the answer...
This is a one mark question so I need the shortest method possible...
2 Answers
- avipLv 71 decade agoFavorite Answer
x^2 + 4x + 5 = 0 has roots
A = -2+i , and B = -2 - i
or x = -2+i , and x = -2 - i
new roots are = X = -2+i+1 , and x = -2 - i + 1
X = -1+i , and X = -1 - i
Req. Eqn = (X +1-i) ( X+1+i) = 0
= x² + 2x +2 =0
Hence Ans: A.
- 1 decade ago
may be you would llike to check the authenticity of the source.The equation has no real roots....
b^2-4ac=16-20 which is negative....none of the options
