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A golf ball is hit with an initial speed of 39m/s at an angle less than 45 degrees above the horizontal.?
If the ball is hit at an angle of 35 degrees, what are the initial horizontal and vertical velocity components?
4 Answers
- 1 decade agoFavorite Answer
What you do is you make a triangle and use soh cah toa. Where the hypotenuse is the 39m/s and the angle that you use soh cah toa with is the 35 degrees and then the legs of the triangle is the x and y or vertical and horizontal parts of the direction the golf ball is traveling.
- DaveWHLv 71 decade ago
If the angle of projection is 35 degrees then
Vertical component = 39 sin 35 = 22.37 m/s
Horizontal component = 39 cos 35 = 31.95 m/s
- 1 decade ago
The required answers are:
horizontal component of velocity = 39*cos 35 = 31.9 m/s
vertical component of velocity = 39*sin 35 = 22.4 m/s
- Anonymous5 years ago
41.27
