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A hot air balloon rises vertically with a speed of 2m/s.?
At the same time, there is a horizontal 8k/h horizontal wind blowing.
What direction is the wind blowing in degrees above horizontal?
Full answer and explanation please.
2 Answers
- 1 decade agoFavorite Answer
im going to assume you meant what direction the balloon will go.
change 2 m/s to 7.2 km/hr because there are 3.6 km/h in 1 m/s
use the pythagorean theorem:
2^7.2 + 8^2 = C^2
C=10.76
Then use cosine to find the angle (a):
cos^-1 8/10.76
= 41.97 degrees above the horizontal
Source(s): I am taking physics. - ?Lv 51 decade ago
Your question makes no sense as it is written. You probably mean to ask what direction above
horizontal the balloon moves.
2m/s should be multiplied by 3600 sec/hour and then divided by 1,000 to get the number of km.
That will give the speed in km/hr, to have the same units as the wind speed.
Then you need to divide the vertical speed by the horizontal wind speed to get a number with no
dimensions. That number will equal the tangent of the angle above horizontal for the total speed
of the balloon. Either use a calculator's inverse tangent function, or look up the arctan of the
calculated number in some math table. I will not give you the answer itself. You will learn nothing
that way.