Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and beginning April 20th, 2021 (Eastern Time) the Yahoo Answers website will be in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.

the determinant of the identity matrix?

i need to prove that the determinent of any sized identity matrix is 1 any ideas on how to do this?

references appritiated (if book references 5 stars given)

Update:

when i said any i meant the general case, i.e. for all identitiy matrices

3 Answers

Relevance
  • ?
    Lv 7
    1 decade ago
    Favorite Answer

    if you know that:

    det(AB) = det(A)det(B) this is easy:

    det(I^2) = (det(I))^2

    but I^2 = I, so det(I) = det(I)^2.

    let x = det(I). then we have x^2 = x

    since I is invertible, x ≠ 0, so we can divide by x to get:

    x = 1.

  • 1 decade ago

    let identity matrix of size 2 X 2

    now determinant = a11 * a22 - a12 * a21 = 1 . 1 - 0.0 =1-0=1

  • 1 decade ago

    No, first you need not settle on the specific ideas

Still have questions? Get your answers by asking now.