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What is the solubility of CdS if it's Ksp is 8.000e-28.?
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- Anonymous1 decade agoFavorite Answer
Note that CdS dissolves as follows:
CdS <==> Cd+(aq) + S-(aq).
Then, K(sp) = [Cd+][S-].
From the balanced equation, we have:
[CdS] = [Cd+] = [S-] = x.
Given that K(sp) = 8.000 x 10^-28:
8.000 x 10^-28 = (x)(x) ==> x = √(8.000 x 10^-28) = 2.83 x 10^-14.
Therefore, since [CdS] = 2.83 x 10^-14, the solubility of CdS is 2.83 x 10^-14 moles per liter.
I hope this helps!
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