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Finding the height of a scalene triangle when given 2 angles and 1 side?
i'm only allowed to use sin(A), cos(A), tan(A), Law of Cosines, and Law of Sines to solve this one.
side c = 1200
Angle A = 72
Angle B = 77
i have to find the altitude/height of the triangle. can someone help me.
A is on the left
B is on the right
c of course makes up AB
i need to find the height from side c to angle C.
i found the answer at answers.com online to be 2159 but how do they get it.
using the formula i found at http://mathforum.org/dr.math/faq/formulas/faq.tria...
i get 1141 which works, so why/how did they come up with 2159.
2 Answers
- vingingeLv 71 decade agoFavorite Answer
The 3 angles of a triangle = 180° so C = 180 - (77 + 72) = 31
Using the Sine Rule : a/Sin 72 = 1200/Sin 31 : a = 1200 x Sin 72/Sin 31 = 2215.89 (2dp)
Area of triangle = ½ac Sin B
Area of triangle = ½ base x altitude = ½c x altitude
Then, ½ac Sin B = ½c x altitude
Altitude = aSin B = 2215.89 x Sin 77= 2159.10 (2dp)