Area of a Segment. Radius is 8cm and Central Angle is 2 degrees?

I am not exactly sure what formula you are using, but you should be using:

A = (1/2)r^2θ, where θ is in radians.

Since r = 8 cm and θ = 2° = π/90, the area of the sector is:

A = (1/2)r^2θ

= (1/2)(8)^2(π/90)

= 16π/45

≈ 1.12 cm^2.

I hope this helps!

I'll be using degrees, not radians (since the given is in degrees)

(Assuming you mean a pizza-slice shaped "segment")

2 / 360 = x / (π(8)²)

2 / 360 = x / (64π)

Multiply by 64π to both fractions

2(64π) / 360 = x

128π / 360 = x

16π / 45 = x

x ≈ 1.12 cm²

The segment has an area of approximately 1.12cm²

the area of a circle is pi*R^2 A circle has 360 stages so a hundred and twenty stages is a million/3 of an entire circle the area of the area is then (a million/3) the area of the circle area of sector = (a million/3)piR^2 = (a million/3)pi*36 = 12pi cm^2 area of sector = 37.7 cm^2

you're doing it right round it to 2