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Sherman81
Lv 6
Area of a Segment. Radius 6.8 and Central Angle is pi/8?
according to the http://mathforum.org/dr.math/faq/formulas/faq.circ...
i should use the formula S = (1/2)xr^2 - (1/2)sin(x)r^2 or ((r^2)/2)(x - sin(x))
so i get S = (((6.8)^2)/2)((pi/8) - sin(pi/8)) = .23156
so i used the Area of a Sector formula.
so
A = (1/2)(pi/8)(6.8)^2 = 9.1
I'm doing online homework, and i've submitted both values and neither one are acceptable.
what the hell is going on.
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