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Solving Systems of Equations? (10 pts)?
salt solutions of 60% and 15% are mixed to produce a 450cm^3 of a 25% solution. How much of each solution is required?
If I let x= the 60% solution and y= the 15% solution,
I ended up with x=325, and y= 125
Is this correct?
1 Answer
- KarenLv 61 decade agoFavorite Answer
Let's see.
x + y = 450 ====> so y = 450 - x
0.6x + 0.15y = 0.25(450)
0.6x + 0.15y = 112.5
substituting:
0.6x + 0.15(450 - x) = 112.5
0.6x + 67.5 - 0.15x = 112.5
0.45x = 45
x = 100 === y = 450 - x = 350
check: 0.6(100) + 0.15(350) = 60 + 52.50 = 112.5
Reality check - we are using 60% and 15% solutions to get a 25% solution. Because 25% is closer to 15% than it is to 60%, we would expect that we would need more of the 15% solution than the 60% solution.
Hope that helps!
