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Motion In Fluid. Please Help Me Solve This Question.?
At a certain point in a pipeline the velocity is 1.00ms^-1 and the gauge pressure is 3.0x10^5 Pa. Find the gauge pressure at a second point in the line 20.0m lower than the first, if the cross section at the second point is one-half that at the first. The liquid in the pipe is water.
3 Answers
- 1 decade agoFavorite Answer
from continuity equation:
A1V1=A2V2
V2=A1V1/A2
V2 = A1V1/(A1)/2 = 2V1 = 2 ms^-1
assume: g = 10 ms^-2 , p= 1000 kgm^-3
Bernoulli's equation is:
P1 + .5pv1^2+ pgh = P2 + 0.5pv2^2 + pg(h-20)
3*10^5 + 500 = P2 + 2000 - 2*10^5
P2 = 4.985*10^5 Pa
Source(s): doing my masters in civil engineering in IIT Madras - 1 decade ago
Giving you the solution to this problem would be unethical, but the clue is Bernoulli's Equation. Find it in your textbook and do a simple substitution of the values, the answer will pop out right-away.
- Anonymous1 decade ago
use Bernoulli's equation.
