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Christina
Christina asked in Science & MathematicsMathematics · 1 decade ago

precalc help please!?

√3 tan (3x) = 0 over [0,2π)

i have no idea how to solve this, please help!

1 Answer

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  • KeplJoey
    Lv 7
    1 decade ago
    Favorite Answer

    Dividing through by √3.

    tan(3x) = 0.

    Note that tan(u) = 0, where u is an integer multiple of π.

    So 3x is an integer multiple of π, so

    x = 0, π/3, 2π/3, π, 4π/3, 5π/3 are the solns.

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