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Circle Geometry: radius and tangent?
The radius of the earth is approximately 6400 km. if the distance from a satellite to the horizon is 1600 km, how far is the satellite above the earth?
This is in my circles geometry unit, as stated in the title.
Describing what the drawing would look like would also be helpful.
Thanks!
to first responder: I just did what you said, and it makes sense, only i got approx. 196 km
2 Answers
- 1 decade agoFavorite Answer
Ever tried the Pythogorean?
height above the earth is sqrt(1600^2 + 6400^2) - 6400 = 1600 (sqrt(17)-4) = 1.96...km
- yancyLv 44 years ago
you like the Derivation: y=sq.(-x² +12) AND y=-sq.(-x² +12) dy/dx= -a million/[2*sq.(-x² +12)]*-2x = (2x)/[2*sq.(-x² +12)] and dy/dx= a million/[2*sq.(-x² +12)]*-2x = -(2x)/[2*sq.(-x² +12)] The Eqationform of a line is y = mx + b m = dy/dx for the two equations now you positioned Your element A interior the Lineform to locate b m = 0 reason, in case you positioned x=0 in our dy/dx varieties you get dy/dx = 0 => y = 0*x + b = b => 5 = b Now you detect the Tangentline y = 5
