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Need help with maths question!?
there are 6 red counters , 3 white counters and a blue counter in a bag. if a counter is chosen at random, noted down and placed back into the bag. find the probability that both choices are red?
Probabilities =
red = 6/10
white = 3/10
blue = 1/10
so would the answer be 12/20 ? , confused!
3 Answers
- 1 decade agoFavorite Answer
This is sampling with replacement which means the probability of an event happening is fixed.SInce there are 6 red counters out of ten, the probability of a red counter being chosen is 6/10 or 0.6. Choosing a red counter in the first draw is 6/10 and choosing a red counter on the second draw is also 6/10. Since the probability of choosing a red counter on the first draw is independent of the second draw, the events are said to be independent and and thus the individual probabilities are multiplied. Thus,we have 6/10 x 6/10 or .6 x 0.6 = 0.36 or 36/100. I hope this clarifies your question. Thanks for asking! Lito Pabriga, (Statistics Consultant- Philippines)
- Anonymous1 decade ago
Bro Ask your teacher . Sincerely .
Source(s): Me