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David
Lv 4
David asked in Science & MathematicsMathematics · 1 decade ago

Need help with maths question!?

there are 6 red counters , 3 white counters and a blue counter in a bag. if a counter is chosen at random, noted down and placed back into the bag. find the probability that both choices are red?

Probabilities =

red = 6/10

white = 3/10

blue = 1/10

so would the answer be 12/20 ? , confused!

3 Answers

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  • 1 decade ago
    Favorite Answer

    This is sampling with replacement which means the probability of an event happening is fixed.SInce there are 6 red counters out of ten, the probability of a red counter being chosen is 6/10 or 0.6. Choosing a red counter in the first draw is 6/10 and choosing a red counter on the second draw is also 6/10. Since the probability of choosing a red counter on the first draw is independent of the second draw, the events are said to be independent and and thus the individual probabilities are multiplied. Thus,we have 6/10 x 6/10 or .6 x 0.6 = 0.36 or 36/100. I hope this clarifies your question. Thanks for asking! Lito Pabriga, (Statistics Consultant- Philippines)

  • 1 decade ago

    yes but then reduce that to 3/5

  • Anonymous
    1 decade ago

    Bro Ask your teacher . Sincerely .

    Source(s): Me
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