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hiya
hiya asked in Science & MathematicsMathematics Β· 1 decade ago

Can someone explain this math problem to me?

I'm proving that the derivative of cotx = (-cscx)^2

the first step is:

let y = (cosx)/(sinx)

the second step is:

[ (-sinx)(sinx) - cosx(cosx) ] / (sinx)^2

Please explain why and how this SECOND step was performed. Thank you!

1 Answer

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  • Anonymous
    1 decade ago
    Favorite Answer

    y = u/v ---> y ' = (u ' v - u v ')/v^2

    with u = cosx ---> u ' = -sinx

    v = sinx --> v ' = cosx

    plug in formula

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