Solve -2(1x+3)-(3x-2)=?

-2(1x + 3) - (3x - 2)

= -2x - 6 -3x + 2

= -5x - 4

Solution :- -2(1x+3)-(3x-2)

= -2x-6-3x+2

=-2x-3x-6+2

= -5x-4

Therefore, -2(1x+3)-(3x-2)= -5x-4

-2(1x+3)-(3x-2)

= -2x-6-3x-2

= -5x-4

therefore -5x=4

x=4/-5

Step one multiply(2x+6)-(3x-2) Step two (2x+3x)-(6+2), Step three(5x-8)

=-2(1x+3) - (3x - 2)

first multiply -2 and (1x+3) and -(minus sign) & (3x - 2) then it becomes,

=-2x - 6 - 3x + 2

=-5x - 4 is your answer.

u must know the following sign rule while multiply

1. (+) X (+) = (+)

2. (+) X (-) = (-)

3. (-) X (+) = (-)

4. (-) X (-) = (+)

imortant topic is that you must look sing of digit. U must look sign before digit. In above case 2 has minus sign, 1x has plus sign and 3x has plus sign.

Another important topic is that , while adding if digits have minus sign we add both digit and write minus sign before digit eg.(-2a -2a =-4a)

and if digit have both minus and plus sign we subtract small digit from large digit we write sign of large digit. eg. (-5 +2 =-3)

= -2x - 6 -3x + 2

=-5x -4

BODMAS

Division then Multiplication then addition then subtraction

-5x-4