4x-8y=16, -2x+5y=55 Solve using elimination method?

4x - 8y = 16

-2x + 5y = 55

▬▬▬▬▬▬▬▬▬▬▬ lets eliminate x

▬▬▬▬▬▬▬▬▬▬▬ multiply the second equation by 2

4x - 8y = 16

-4x +10y = 110

▬▬▬▬▬▬▬▬▬▬▬ add the two equations

0x +2y = 126

▬▬▬▬▬▬▬▬▬▬▬ solve for y

y = 63

▬▬▬▬▬▬▬▬▬▬▬ solver for x by substitution

4x - 8y = 16

4x - 8(63) = 16

4x - 504 = 16

4x = 520

x = 130

I hope this helps!

Equation 1: 4x-8y=16

Equation 2: -2x+5y=55

Multiply Equation 2 by 2 ---> -4x+10y=110 (we can name it equation 3)

Add equation 1 & equation 3

(4x-4x)+(-8y+10y)=16+110

2y=126 ---> y=63.

Compensate in equation 1

4x-8*63=16 ---> 4x=16+504 ---> x=130.

X=130 & Y=63

First, you multiply the second one by 2: -4x + 10y = 110

Then you put both together: 4x - 8y - 4x + 10y = 16 + 110

-> 2y = 126 -> y = 63

4x - (8x63) = 16

4x= 520

x = 130

4x-8y=16 (1)

-2x+5y=55 (2)

(2) x -2

4x-10y= -110 (3)

(3) - (1)

-18y = -126

Therefore,

y = 7 (4)

(4) ---> (1)

4x - 8(7) = 16

4x - 56 = 16

4x = 72

Therefore,

x = 18

I hope this helped :)

4x-8y=16

-2x+5y=55

4x-8y = 16 -------->(I)

-2x+5y = 55 -------->(II)

Multiply Eq. II by 2

4x-8y = 16

-4x+10y = 110

----------------------

2y = 126 (+4x and -4x cancels out)

y = 63

Put value of y in either eq. (we put in eq I here)

4x-8*63 = 16

4x-504 = 16

4x = 16+504

4x = 520

x = 520/4

x = 130

So, x = 130 & y = 63