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Help with these Physics Problems?
I had to take a basic Intro To Physics class this year, and I did not do well in it at all. Math and I do not mix, Math does not stick with me. But, I need to do these problems to get a credit for the course. I have no idea what I am doing, anything would help. The problems are listed as:
1) Calculate the torque applied into the road by a tire if the diameter of the tire is 0.4 m and the axle exerts 340 N of Force.
2) Calculate the ammount of heat energy required to raise the temperture of a 5kg block of solid platinum from 0 degrees celsius. The specific heat of platnium is 133 J/kg K. How much heat energy is required to raise a 5 kg of water by the same ammount. The specific heat of water is 4.2 k/kg K
2 Answers
- 10 years agoFavorite Answer
the answer to 1st q question will be
torque=340*0.2 = 68Nm
i think the 2nd question is incomplete.The range of temperature is not specified.From 0 degrees to ??
- blauserLv 45 years ago
D = 55ft. t = sqrt(2D/g) t = sqrt(110ft/32ft/s^two) t = a million.86s I don't have any concept the way you obtained zero.33s. Which in case you paintings it out backwards and also you remedy g. g = 2D/t^two g = 1010ft/s^two Acceleration = Velocity / Time Velocity = Distance / Time Essentially Acceleration = (Distance / Time) / Time = Distance / (Time)^two aka Distance over seconds squared. So no, you are not able to forget about the seconds squared while fixing for time that is squared. So you have got to rectangular root the time in an effort to get the genuine importance of time, and no longer time squared.
