Error in my Java function?

Question

Hi.

Here is my Java function:

public  String ecrire(){
  String  temp="";
  for(int  i=0;i<grille.length;i++){
  for(int  e=0;e<grille[i].length;e++){
  Temp+=Integer.toString(grille[i][e]);
  }
  }
  temp+=" //  "+Integer.toString(lacomplexite);
  return Temp;
  }

It's not working, but I don't know what the problem is... And what should my result be in the end?

Thanks!

deonejuan · Accepted Answer

1. You have 'Temp' and you have 'temp'. Java is case-sensitive
2. if grille has been declared but nothing put in it, you won't get anything

int[][] grille = {
{1,2,3,4,5,6,7},
{11,12,13,14,15,16,17},
{21,22,23,24,25,26,27}
};

public String ecrire() {
String temp ="";
for( int i = 0; i< grille.length; i++) {
for( int j = 0; j < grille[ i ].length; j++ ) {
temp += grille[ i ][ j ] + ",";
}
return temp;
}
System.out.println( ecire() );
// try that, and note I call the method() with ecire()

Kevin Lain · Answer

How do you know it's not working if you don't know what the result should be? ^_^;

I don't have Eclipse, or Java for that matter installed on this computer so I can;t compile this or anything but just looking at it,


Temp does not seem to be delcared, is it a global variable?
Remember that capital letters are important in Java, A is not equal to a, Temp is not the same as temp.

And what is grille. I don;t understand what data type this could possibly be ^_^; is it a one dimension or 2 dimension integer array?

Vaibhav · Answer

java is case-sensitive so Temp and temp are different
also to convert int to string use
String.valueOf(grille[i][e]);
same way at end

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Error in my Java function?

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