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Find n (secondary school maths)?
I am currently stuck on this question. Could anyone help? Please show/explain the working out if possible. Thanks!
Update:
Just an incentive: first person to answer gets 10 points. ;D
1 Answer
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- ?Lv 710 years agoFavorite Answer
4n^(3/2) = 8^(-1/3) = 1/(8^(1/3)) = 1/2
so n^(3/2) = 1/8
so n^3 = 1/64
n = cbrt(1/64) = 1/4
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