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Anonymous
Anonymous asked in Science & MathematicsMathematics · 10 years ago

Solve the equation.. absolute value of [x] = x/2 + 3?

Solve the equation using algebra

[x] = x/2 + 3

5 Answers

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  • Anonymous
    10 years ago
    Favorite Answer

    (I use the | x | notation for the absolute value of x)

    Case 1 (x>=0):

    x=x/2 + 3

    2x=x+6

    x=6 (which satisfies x>=0)

    Case 2 (x<0):

    -x=x/2 + 3

    -2x=x+6

    3x= -6

    x= -2 (which satisfies x<0)

    so x = -2, 6

  • 10 years ago

    If x>0 |x|=x so x=x/2+3 so x=?

    If x<0 |x|=-x so -x=x/2+3 so x=?

  • 10 years ago

    x^2 - (x/2+3)^2=0

    (x-x/2-3)(x+x/2+3)=0

    X/2=3. So x= 6. Or 3x/2=-3. X=-2

  • 10 years ago

    |x| = x/2 + 3

    let x<0

    |x|=-x

    hence

    -x = x/2 + 3 => x₁=-2

    let x>=0

    |x|=x

    hence

    x = x/2 + 3 => x₂=6

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  • 10 years ago

    Well multiply each side by 2 and get 2x= x + 3 then subtract the x from the 2x and get x=3

    Source(s): My brain
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