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How do you solve these algebra problem?

Problem1

3/5(x+2)=y

Problem 2

3x+xy=8

Solve for x

1 Answer

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  • 10 years ago
    Favorite Answer

    You solve for x by reversing all the operations surrounding x, from the outside in.

    3x+xy=8

    First, we need to get a single x on one side.

    Use the distributive law:

    x(3+y) = 8

    Now, the outermost operation is multiplying by (y+3).

    We apply the inverse operation: *divide* both sides by (y+3):

    x = 8/(y+3)

    ... and we're done.

    Now, can you apply those principles to the first one?

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