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How do you solve these algebra problem?
Problem1
3/5(x+2)=y
Problem 2
3x+xy=8
Solve for x
1 Answer
- norcekriLv 710 years agoFavorite Answer
You solve for x by reversing all the operations surrounding x, from the outside in.
3x+xy=8
First, we need to get a single x on one side.
Use the distributive law:
x(3+y) = 8
Now, the outermost operation is multiplying by (y+3).
We apply the inverse operation: *divide* both sides by (y+3):
x = 8/(y+3)
... and we're done.
Now, can you apply those principles to the first one?