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Integrated algebra problem. Just 1 question please help?
An oil company distributes oil in a metal can shaped like a cylinder than has an actual radius of 5.1 cm
and a height of 15.1 cm. A worker incorrectly measured the radius as 5 cm and the height as 15 cm determine the relative error in calculating the surface area, to the nearest thousandth.
1 Answer
- Neil KelceyLv 610 years agoFavorite Answer
SA(cylinder) = 2πrh + 2πr²
IF
• the desired "r" and "h" values are 5.1 cm and 15.1 cm respectively,
THEN
• the desired SA = 2π(5.1)(15.1) + 2π(5.1)² = 2π(103.2) cm²
The flawed can's SA = 2π(5)(15) + 2π(5)² = 2π(100) cm²
RE = | error from desired | ÷ desired
RE = |2π(103.2) – 2π(100)| ÷ 2π(103.2)
RE = 3.02 ÷ 103.2
RE = 0.0231...
RE = 0.023 (n. thousandth)
BTW ...
RE (as a %) = 2.3%
Hope this helps! Cheers! :)
.
Source(s): . http://mathworld.wolfram.com/RelativeError.html . http://en.wikipedia.org/wiki/Approximation_error . https://ece.uwaterloo.ca/~dwharder/NumericalAnalys... .