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help with factions? pre-algebra?
i totally forgot how to do these? i must sound dumb but i do need help with these. i forgot how to do it with the variable. i just need to put these into simplest form. i just need an explanation on these. i can figure out the rest...
5/3 + k/5 (wouldn't the 5's cancel out and the answer be 3k?)
3s/4 + 5/6=?
2f/5 +g/6=?
1/a + b/2=?
1/x + 2/xy=?
4 Answers
- Iggy RockoLv 710 years agoFavorite Answer
5/3 * k/5 = 3/k but you're adding, not multiplying
5/3 + k/5 = (5/5)(5/3) + (3/3)(k/5) = 25/15 + 3k/15 = (25 + 3k)/15
3s/4 + 5/6 = (3/3)3s/4 + (2/2)5/6 = 9s/12 + 10/12 = (9s + 10)/12
2f/5 + g/6 = (6/6)2f/5 + (5/5)g/6 = 12f/30 + 5g/30 = (12f + 5g)/30
1/a + b/2 = (2/2)1/a + (a/a)b/2 = 2/(2a) + ab/(2a) = (2 + ab)/(2a)
1/x + 2/(xy) = (y/y)1/x + 2/(xy) = (y + 2)/(xy)
- Anonymous10 years ago
5/3 + k/5
nope the 5's do not cancel
with these fractions the aim is to get the bottom of both fractions the same
5/3 + k/5 = (5*5 + k*3) / 15 = (25+3k)/15
3s/4 + 5/6
(3s*6 + 5*4)/ 24 = (18s +20)/24
Hope this helps u do the rest
- Jun AgrudaLv 710 years ago
= 5/3 + k/5
= (5[5] + 3k)/(3[5])
= (25 + 3k)/15
Answer: (3k + 25)/15
-----------
= 3s/4 + 5/6
= (3[3s] + 2[5])/12
= (9s + 10)/12
Answer: (9s + 10)/12
-----------
= 2f/5 + g/6
= (6[2f] + 5g)/30
= (12f + 5g)/30
Answer: (12f + 5g)/30
-----------
= 1/a + b/2
= (2b + a)/2ab
Answer: (2b + a)/2ab
-----------
= 1/x + 2/xy
= (y + 2)/xy
Answer: (y + 2)/xy
- 10 years ago
5's cannot be cancelled because its addition. Use 5 as your LCD (Least Common Denominator) and then follow the process of adding fractions. For the rest of the problems, just find the LCD before proceeding to the process.