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Raia
Lv 4
Raia asked in Science & MathematicsMathematics · 10 years ago

How would you solve radical 72 with factoring?

I know that it's radical ( 9 * 2 * 4) and that the next step would be 3 (radical) (2 * 4). Since the square root of 4 is 2, would the final answer be 12 (radical) 2 or 7 (radical) 2?

I'm not sure if you multiply or add the square root factors to the outside. Thanks!

Update:

I see that I mixed up the 2 and 4. Thanks!

4 Answers

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  • Kristine
    Lv 5
    10 years ago
    Favorite Answer

    6sqrt2

  • M. Wiley
    Lv 5
    10 years ago

    You're right, the stuff in the radical is (9*4*2), which we can also write as (3^2 * 2^2 * 2).

    The stuff that we pull out of the radical is multiplied together, giving us

    3*2 * radical(2)

    or

    6 * radical(2)

    Notice also that 6*6 = 36, and 36 * 2 = 72, so you can work backwards to check your answer.

  • Pranil
    Lv 7
    10 years ago

    √72 = √36 × 2

    = 6√2

    √72 = √9 × 4 × 2

    = 3 × 2 √2

    = 6√2

    ----

  • Maki
    10 years ago

    sqrt72

    =sqrt36 multiplied by sqrt2

    =6sqrt2

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