Physics Problem HELP!! Forces!?

it's simply F = mg cos45 since F is balanced with the weight force component that's perpendicular to the surface.

so F = 1.28 x 9.8 x cos45 = 8.87 N <<<<<<<<<

For bottle not to move, sum of all components of every force must be 0. Forces affecting the bottle are gravitational force and 2 surface forces. So the sum of horizontal components of forces must be 0 (as the bottle doesn't move and there is no horizontal component of gravitational force) and the sum of vertical components must be the same magnitude as gravitational force.

F = cos(a)* F(1) + cos(a) F(2) .... F is sum of vertical components of forces.

F = -F(g) = 1.28*9.8=12.544

The horizontal components of F(1) and F(2) must be equal (as bottle does not move):

F(1)*sin(a)=F(2)*sin(a).

I don't have the drawing, but I'd assume both surfaces are at 45° angle. Which makes

F(1)=F(2) -> F= cos(a) * F1 * 2.

F(1)=F(2) = F / (2*cos(a)) = 8.87N

Sum Fx = zero and Sum Fy = zero Sum Fx = F1,x + F2,x + F3,x = zero + forty four cos 60 + F3,x = 22 + F3,x = zero. So, F3,x = -22 N. Sum Fy = F1,y + F2,y + F3,y = 33 + forty four sin 60 + F3,y = 33 + forty four sin 60 + F3,y = zero So, F3,y = -seventy one N. F3 = sqrt [ F3,x ^two + F3,y ^two ] = sqrt [ (-22)^two + (-seventy one)^two ] = seventy four N. Direction of F3 = a hundred and eighty + tan^(-a million) (seventy one/22) = a hundred and eighty + seventy three = 253 deg.