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How long does it take?
An ball is dropped from 6.0m above the ground. This means that the initial velocity is 0m/s. Ignoring air resistance, how long does it take before it hits the ground? What is the formula to figure this out too please. I want to know how to figure it out, not just the answer. Thanks.
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- SteveLv 710 years agoFavorite Answer
t = √[2y/g] = √[2*6.0/9.8] = 1.107 sec
Source(s): Eqs of constant acceleration
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