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Can you differentiate this?
5ln 2t
differentiate with respect to t
so far I've put it to the power of 5 (ln 2t)^5 but i don't get how to differentiate inside the bracket
2 Answers
- Daaa :)Lv 410 years agoFavorite Answer
Ln u = u'/u
So:
y = 5ln 2t
y' = 5 * (2t)' / 2t -->> And 2t' = 2
y' = 10/2t = 5t
- ?Lv 710 years ago
iT IS DY/DT = 5 / t
if you did y= ln (2t)^5 , dy/dx = (1/(2t)^5 ) d/dt (2t)^5
d/dt (2t)^5 = 5(2t)^4 d/dt (2t)
= 10 (2t)^4
dy/dx = (1/(2t)^5 ) (10 (2t)^4)
dy/dx= 10 /(2t) =5 / t