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how do you find the amount of Joules gained by a calorimeter (gen chem help)?
Given
HNO3 + KOH --> KNO3 (aq he) + H20
the heat gained by the calorimeter and the heat of the reaction (assume the density and the specific heat are the same as distilled water):
Temp of 50.0 mL of HNO3 before mixing : 22.0 degrees Celsius
Temp of 50.0 mL of KOH before mixing : 22.0 degrees Celsius
Temp of 100.0 mL of reaction mixture : 34.5 degrees Celsius
how many joules are gained my the solution, how many joules are gained by the calorimeter and what is the heat of reaction?
1 Answer
- ?Lv 710 years agoFavorite Answer
50ml HNO3 = 50g
50ml KOH = 50g
100g x 4.184J/g-ºC x 12.5ºC = 5230J = heat gained by the solutions
5230J = heat of reaction
both the calorimeter and the liquids have the same temperature throughout the reaction so they have the same deltaT
Q = heat rxn + heat cal
Qtcal = Ccal x deltaT
Qwater = Cwater x deltaT
both the water and calorimeter have the same temperature
so, since they share the same deltaT
C system = C water + C cal
heat absorbed by solution = 4.184J/ºC x 12.5ºC = 52.3J
so, the rest of it has to be the heat absorbed by the calorimeter = 5230 - 52.3 = 5177.7J